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LAMC
BIOLOGY

Bio3: Quiz 4 Study Guide - Spring 2006

Topics:

Note: The quiz will contain questions that are similar, but not identical to, the study questions below and the lab review sheet questions.
The quiz will cover lab topics for week 9 (Mitosis & Meiosis), 10 (Genetics 1) and 11 (Genetics 2)
You should be able to:
- draw the different stages of mitosis and meiosis
- calculate the number of chromosomes in diploid and haploid daughter cells
- calculate the possible number of unique daughter cells that are formed during meiosis
- solve genetics problems for singe gene and double gene crosses
- explain the function of restriction enzymes and how they are used to identify a person’s DNA
- interpret gel electrophoresis DNA data

Study Questions:

In humans, albinism (c) is recessive and normal pigmentation (C) is dominant. 

1. If a CC individual mates with a cc individual, what are the expected genotype and phenotype ratios of the offspring?

2. A normally pigmented male mates with an albino woman.  One of their children is albino.  What are the genotypes of the two parents?  What are the expected genotype and phenotype ratios of all their children?

In the fruit fly, the long-wing gene (L) is dominant and the short-wing gene (l) is recessive.

3. Two long-winged flies mated and had 12 long-winged offspring and 4 short-winged offspring.  What are the genotypes of the two parents?

4. A long winged fly mated with a short-winged fly.  All of their offspring are long-winged.  What are the genotypes of the parents?

In guinea pigs, rough-coat (R) is dominant and smooth coat is recessive (r).  Also, black (B) is dominant and white (b) is recessive.

5. A rough-coated, black guinea pig, whose mother was smooth and white, mates with a smooth and white pig.  What are the expected the phenotype and genotype ratios for their offspring?

6. A rough, black guinea pig mated with a rough, white guinea pig yields the following offspring: 28 rough and black, 31 rough and white, 11 smooth and black, 9 smooth and white.  What are the genotypes of the parents?

7. Can a man be homozygous for a sex-linked trait located on the X chromosome?  From which parent does the man receive this sex-linked gene?

8. A woman of normal vision, whose father was color-blind, marries a man with normal vision whose maternal grandfather was color-blind.  What are the genotypes of the parents?  What are the expected genotype and phenotype ratios of their children? (Note: normal vision (N) is dominant and color-blindness (n) is recessive)

Answers:

1. 100% Cc (normal pigmentation)
2. male is Cc, female is cc.  Genotype ratio: ½ Cc, ½ cc, phenotype ratio: ½ normal, ½ albino
3. Ll
4. LL and ll
5. RrBb x rrbb Phenotype ratio: ¼ rough and black, ¼ rough and white, ¼ smooth and black, ¼ smooth and white.  Genotype ratio: ¼ RrBb, ¼ Rrbb, ¼ rrBb, ¼ rrbb
6. RrBb x Rrbb
7. No, because he will always have only one copy of the allele.  He receives it from his mother.
8. X^NXⁿ x X^NY Expected genotypes: ¼ X^NX^N, ¼ X^NXⁿ, ¼ X^NY, ¼ XⁿY.  Expected phenotypes: ¾ normal, ¼ color-blind.

©2003-2004 Dilek Sanver-Wang, MS
Los Angeles, CA USA.  All Rights Reserved.